SetOctString_BN¶
Converts octet string into a positive Big Number.
Syntax¶
IppStatus ippsSetOctString_BN(const Ipp8u* pStr, int strLen, IppsBigNumState* pBN);
Include Files¶
ippcp.h
Parameters¶
pStr |
Pointer to the input octet string. |
strLen |
Octet string length in bytes. |
pBN |
Pointer to the context of the output Big Number. |
Description¶
This function converts an octet string into a positive Big Number.
Return Values¶
ippStsNoErr |
Indicates no error. Any other value indicates an error or warning. |
ippStsNullPtrErr |
Indicates an error condition if any of the specified pointers is NULL. |
ippStsContextMatchErr |
Indicates an error condition if the context parameter does not match the operation. |
ippStsLengthErr |
Indicates an error condition if specified strLen is less than 1. |
ippStsSizeErr |
Indicates an error condition if insufficient space has been reserved for Big Number. |
Example¶
The code example below shows how to create a big number from a string.
void Set_BN_sample(void){
// desired value of Big Number is 0x123456789abcdef0fedcba9876543210
Ipp8u desiredBNvalue[] = "\x12\x34\x56\x78\x9a\xbc\xde\xf0"
"\xfe\xdc\xba\x98\x76\x54\x32\x10";
// estimate required size of Big Number
//int size = (sizeof(desiredBNvalue)+3)/4;
//int size = (sizeof(desiredBNvalue)+3)/4;
int size = (sizeof(desiredBNvalue)-1+3)/4;
// and create new (and empty) one
IppsBigNumState* pBN = New_BN(size);
// set up the value from the srting
ippsSetOctString_BN(desiredBNvalue, sizeof(desiredBNvalue)-1, pBN);
Type_BN("Big Number value is:\n", pBN);
}